I don't think i'm setting this systems of equations word problem up correctly...if not how?
Tickets for one show on the Harlem Globetrotters' 75th Anniversary Tour cost $10, $18, or, for VIP seats, $30. So far, five times as many $18 tickets have been sold as VIP tickets. The number of $10 tickets equals the number of $18 tickets plus twice the number of VIP tickets. Sales of these total $9500. How many of each kind of ticket have been sold?
I tried to set it up like this but it doesn't work out to the right answer. Am I setting it up incorrectly?
If -
$10 = T
$18 = E
$30 = V
E = 5V
T = E + 2V
E + T + V = $9500
2007-03-23 17:50:45 · 6 answers · asked by World Expert 1 in Education & Reference ➔ Homework Help
Your mistake is in the initial setup
T= the cheap Totally tickets (ie $10 tickets)
E = the Economical tickets (ie $18 tickets)
V= the VIP tickets (ie the $30 tickets)
The next equations were correct.
E = 5V
T = E + 2V
the last one was the wrong one
it should read:
$10 x T + $18 x E + $30 x V = $9,500
E, T and V are quantities (not money) Therefore, E + T + V can not give you any results with dollar amount. That is why you need to multiply them by their value.
Hope this helps for your next problem.
2007-03-23 18:06:39 · answer #1 · answered by 2 Wheel Dragster 3 · 0⤊ 0⤋
$30 VIP tickets= X
$18 = 1/5X
$10= 11/5X
10(11/5X)+ 18(1/5X) + 30(X) = 9500
22X+ 18/5X + 30X= 9500
278/5X=9500
278X= 47,500
X=171
$30 = 171 Tickets
$18 = 34 Tickets
$10 = 376 Tickets
2007-03-24 01:06:58 · answer #2 · answered by thewiseman2008 3 · 0⤊ 0⤋
given that T, E and V correspond to the number of tickets, E+T+V does not equal $9500 but 10T + 18E + 30 V = 9500 - this should get you on the right track.
2007-03-24 01:01:19 · answer #3 · answered by Sarah Morgan-White 2 · 0⤊ 0⤋
t = number of $10 tickets
e = number of $18 tickets
v = number of $30 tickets
The variables should be what you're trying to find; in this case, the number of each type of tickets that were sold.
That should get you closer to the correct answer.
2007-03-24 01:00:14 · answer #4 · answered by Anonymous · 0⤊ 0⤋
A= Number of $10 tickets sold.
B= Number of $18 tickets sold.
C= Number of $30 tickets sold.
10(5C+2C) + 18(5C) + 30C = 9500
10(7C) + 18(5C) + 30C = 9500
70C + 90C + 30C = 9500
190C = 9500
C = 50
B = 5(50)
B = 250
A = 250 + 2(50)
A = 250 + 100
A = 350
A = 350
B = 250
C = 50
2007-03-24 03:25:12 · answer #5 · answered by qareporting 3 · 0⤊ 0⤋
I got outta Algebra so im not sure!
2007-03-24 01:59:57 · answer #6 · answered by Anonymous · 0⤊ 0⤋