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find the slope of the line through the following pairs of points(-5,-3) and (-5,2)

2007-03-23 14:03:45 · 8 answers · asked by APRIL 2 in Education & Reference Homework Help

8 answers

-3 - 2 = -5
-5 - -5= 0

the slope is undefined.

the line goes up and down, passing through -5

2007-03-23 14:08:09 · answer #1 · answered by l* 2 · 0 0

The slope is undefined

2+3=5
-5+5=0

it is a vertical line so the slope is undefined

2007-03-23 14:12:49 · answer #2 · answered by linkin_brandon 2 · 0 0

You take the two points, (-5,-3) and (-5,2) and try to figure out m.
(y-y, x-x)
-3-2
-5-(-5)

-5/0

The slope is undefined, there is a straight vertical line running through -5.

2007-03-23 15:00:13 · answer #3 · answered by kim 2 · 0 0

a simple way to solve it is just to graph the two points and connect them. then you can figure out the slope. since it is a vertical line, the slope is undefined.
or you could use algebraic method:
m(slope)=(y1-y2)/(x1-x2), where y1 and y2 are the y-points and x1 and x2 are the x-points.
m=(-3-2)/(-5-(-5))
m=-5/0, which is not a real number, so the slope is undefined.

2007-03-23 15:05:41 · answer #4 · answered by Ch 3 · 0 0

21. y=.6x+3 22. y=-1x+9 23. y=-.86x+4.40 3 24. y=-4.5x+4 50. y=-4x-7 fifty one. y=(7/2)x+14 fifty two. y=-(3/9)x+a million fifty 3. y=-(3/8)+6.5 fifty 4. y=2x-sixteen fifty 5. y=5X-15 listed right here are the solutions. Use the formula y=mx+b , and slope formula (y1-y2)/(x1-x2).

2016-10-19 11:32:32 · answer #5 · answered by ? 4 · 0 0

that's a vertical line y= -5 .. so the slope is undefined..

but to get the slope - it is rise/run, meaning (y1-y2) / (x1-x2)

you gotta plug in the points in that equation.

2007-03-23 15:37:27 · answer #6 · answered by pinai b 2 · 0 0

slope = (y2-y1)/(x2-x1)
so, m = (2- -3)/(-5- -5)
= 5/0
= 0
slope = 0
So, it is a straight vertical line

2007-03-23 14:12:28 · answer #7 · answered by gamma_wave 3 · 0 0

y2-y1 2- -3 5
--------- -------- ------
x2-x1 -5 - -5 0

slope 5
--
0 or 5

slope is undfined

2007-03-23 14:14:49 · answer #8 · answered by just tht kid over there 3 · 0 0

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