Chemistry question...?

Question

The question is how many geometric isomers can exist of the complex [Cr(dmen)3]3+. I don't understand even how to figure out how many geometric isomers it can have in the first place. I don't want the answer solely, but how to solve it, so I can solve them in the future. Any tips would be super great!!

Answer 1

It 's been too long since I did these sort of problems so I am rather rusty.

First of all look at your ligand. It is bidentite (divalent) so your co-ordination number is 2*3=6. Thus you will have an octahedral arrangement.

Also your ligand is assymetrical. So for example if you had the complex [Cu(dmen)2](+2) you would have

. .. .. .. .. .. ___ .. .. .. .. .. .. .. .. .. ___
. .. .. .. .. ../.. .. .\ .. .. .. .. .. .. .. .. / .. .. .\
. (CH3)2N .. .. NH2 . (CH3)2N .. .. ..NH2
.. .. .. .. .. .. Cu .. .. .. .. .. .. .. .. .. .. Cu
. (CH3)2N .. .. NH2 .. .. .. .H2N .. .. ..N(CH3)2
.. .. .. .. .. .\___/ .. .. .. .. .. .. .. .. .\___/
.. .. .. .. .. .. cis .. .. .. .. .. .. .. .. .. .. trans


So you have to find out in how many different ways you can put the 3 ligand molecules in the octahedral arrangement
However I am not sure how you would name them;
You will also have optical symmetry, increasing the number of isomers

You have fac and mer isomers
fac are with all N(CH3)2 groups on one face of the octahedron and mer with two of them on the axis and 1 on the plane.
You also have isomers where all N(CH3)2 are on the plane or at least one is on the axis but I don't know how you would call them (maybe equatorial vs axial) Then you would have all equatorial, diequatorial axial and diaxial equatorial.
The two latter would be fac mer isomers to each other.

I think there are 6 different structures (the 3 types I told you based on the axial-equatorial positions x 2 optical isomers for each; some of them are fac-mer to each other but this doesn't increase the number of isomers) thus 6 geometric isomers. I am not 100% sure, though.

Answer 2

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