When 0.130 g of Fe is added to 125.0 mL of 0.683 M HCl, the metal reacts to make FeCl3(aq) and H2 gas.?

Question

When 0.130 g of Fe is added to 125.0 mL of 0.683 M HCl, the metal reacts to make FeCl3(aq) and H2 gas.
Assuming constant volume, what is the molarity of FeCl3(aq) (unit = mol/L)?

Fe3+ ions? (unit = mol/L
Cl- ions? (unit = mol/L)

Answer 1

1. Write the balanced equation.
2. Calculate moles of HCl from volume and M of HCl.
3. Calculate moles of Fe from mass of Fe.
4. Determine limiting reactant using info from 1-3.
5. Using limiting, calculate moles of FeCl3.
6. Using moles of FeCl3 from 5, calculate M (assuming constant volume).
7. There are 3X more Cl- ions than Fe+3 ions, so Cl- ions will be 3X the M from 6 above.