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A capacitor is constructed from two square
metal plates. A dielectric k = 2.05 fils the
upper half of the capacitor and a dielectric
k = 6.6 fills the lower half of the capacitor.
Neglect edge effects.
Calculate the capacitance C of the device.
Answer in units of pF

2007-03-23 05:12:39 · 2 answers · asked by kpm0729 1 in Science & Mathematics Physics

2 answers

Consider this as follows

| C1 |
|------|
| C2 |

This is equivalent to two capacitors in parallel. Capacitors in parallel act like resistors in series.

C1 = 2.05*C, where C is the equivalent air filled capacitor

C2 = 6.6*C

Total C = C1 + C2 = 8.65*C

However, I think that we need the area of the plates (C1 and C2 will each have half) and the distance that separates them to work out the capacitance numerically.

2007-03-23 05:22:22 · answer #1 · answered by dudara 4 · 0 0

You need to tell us whether 'the upper half' refers to
'half of plate area' or 'half of the gap'. Are the
plates horizontal or vertical? It affects the effective
schematic diagram as parralel or series.

Good thing, though, that you did not specify
the numeric values of capacitor dimensions.
I suppose you want the general formula, and are
willing to do actual numeric calculations yourself.

2007-03-23 07:00:56 · answer #2 · answered by Alexander 6 · 0 0

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