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5 answers

Umm what?

I mean.... if it has to affect the light rays than it should be visible(400 - 700 nm) too right...

If its not visible how else can it affect visible rays??

Cheers!!!

2007-03-23 04:58:47 · answer #1 · answered by ? 3 · 0 0

The question is a bit unclear, and it supports multiple answers.

Under usual conditions, no ray can affect visible light rays. Just point a flashlight at a wall at night, then take a second flashlight and point it so that its light crosses the path of the light from the first flashlight. No matter how intense is the second flashlight, the light on the wall is not affected, unless the second flashlight is also pointed there.

With abnormal conditions, that is another story. In some materials, high intensity light can change the properties of the material, and other light propagating through the material is changed. For example, infrared light from a laser, put through certain crystals, will generate visible light. But the light intensity required for this effect is so high that if it gets into your eye, it will damage it permanently. There are experimental lasers which can generate light intensities so high that air will be ionized in its path (similar to a flame), and this will absorb any light passing through it. There are also other types of rays - alpha and beta - which, being particles (helium nuclei and electrons, respectively) will scatter light, and change its wavelength depending on scattering direction (Compton effect).

But all these situations require a medium to affect the visible light. Without any medium (in vacuum), light rays can not be affected by any light ray.

And to comment another answers, infrasound and ultrasound are not rays, but waves, and are not invisible, but inaudible.

2007-03-23 10:50:51 · answer #2 · answered by Daniel B 3 · 0 0

infrasonic or ultrasonic rays. they both r visible but invisible to humans, only animals like dogs and dolphins can see them.

2007-03-23 05:17:40 · answer #3 · answered by tia 1 · 1 1

sun rays

2007-03-23 04:56:07 · answer #4 · answered by Beliver 2 · 0 0

Plz explain your question a little.

2007-03-23 17:39:46 · answer #5 · answered by girish k 2 · 0 0

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