A bicycle leaves town at 15 miles per hour at 8:00 am. and a car leaves at 11:00 am. traveling in the same direction at 60 miles per hour. How many min. after 11:00 am will it be when the car overtakes the bicycle?
2007-03-23 03:50:31 · 4 answers · asked by whittany p 1 in Science & Mathematics ➔ Mathematics
Distance = velocity * time
Let x be the time in hours of the car travel, making the time of bike travel 3 hours longer (3 + x)
When the distances are equal,
15(3 + x) = 60x
45 + 15x = 60x
45 = 45x
x = 1 hour = 60 minutes
2007-03-23 03:54:25 · answer #1 · answered by MamaMia © 7 · 0⤊ 1⤋
The bicycle has a 3 hour headstart
During this time it will have been 15*3=45 miles ahead of the car
Let x be the number of hours the car will take to overtake the bicycle
60x = 15x + 45
45x = 45
x = 1
Therefore, the car will take 1 hour (60 mins) to overtake the bicycle
2007-03-23 03:55:25 · answer #2 · answered by Ashley 2 · 0⤊ 0⤋
61 minutes.
The will both be at the same place at 60 minutes (1200 PM) -- If the bikes travel 15 miles each hour, by 12:00 PM, it will have traveled a total distance of 60 miles. The car travels 60 miles in the first hour.
2007-03-23 03:59:10 · answer #3 · answered by Me 1 · 0⤊ 0⤋
i dont know this answer to your question get a book and look it up.
2007-03-23 03:54:28 · answer #4 · answered by michelle a 2 · 0⤊ 1⤋