English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

2x(squared)-3x-4=0
by the way thanks to the awesome people that helped me in my previous questions!!!!!!!!!luv yall ... please help me in this question

2007-03-23 03:13:04 · 9 answers · asked by barcaroni2009 1 in Science & Mathematics Mathematics

9 answers

The quadratic cannot be factored in terms of integers, so the final answer has to be the same as the original expression.

Go to www.quickmath.com and click on the Quadratics link along the left. Plug in your formula and see what I'm talking about. BTW you will LOVE the Quickmath site. They even walk you through the solution.

2x^2-3x-4

3 +- sqrt of 9 - (4*-8) =

3 +- sqrt of (9+32) / 4=

3 +- sqrt of (41) / 4

These roots are irrational, the quadratic cannot be factored in terms of integers.

2007-03-23 03:22:23 · answer #1 · answered by Cambion Chadeauwaulker 4 · 1 0

2x^2 - 3x - 4 = 0
Using formula for roots of a quadratic equation
x = 3 +/- sqrt(9+32)/2

x = 3/2 + sqrt(41)/2 or x = 3/2 - sqrt(41)/2

Answer x = (-4.9031,7.9031)

2007-03-23 10:21:22 · answer #2 · answered by Nishit V 3 · 0 1

Quadratic Equation

x = - b ± √b² - 4ac / 2a

x = - (- 3) ± √(-3)² - 4(2)(- 4) / 2(2)

x = 3 ± √9 - (- 32) / 4

x = 3 ± √9 + 32 / 4

x = 3 ± √41 / 4

x = 3 ± 6.403124237 / 4

- - - - - - - - - -

Solving for +

x = 3 + 6.403124237 / 4

x = 9.403124237 / 4

x = 2.350781059

- - - - - - -

Solving for -

x = 3 - 6403124237 / 4

x = -3.403124237 / 4

x = - 0.850781059

- - - - - - -s-

2007-03-23 10:49:26 · answer #3 · answered by SAMUEL D 7 · 0 1

2x^2 - 3x - 4 = 0
a b c
use the formula for quadratic equations ( x=-b +or- root of b^2-4ac/2a)

x= --3+or- [root of (-3)^2-4(2)(-4)]/2(2)
x=3+or- [root of 9+32]/4
x=3+or- [root of 41]/4
or you can simplify it to decimal form
x= (-0.64921894... , 2.350781059...)
round to nearest 1000th
x= about (-0.649, 2.351)

Answer x = (-4.9031,7.9031)

Hope that helps!

2007-03-23 10:35:53 · answer #4 · answered by BlueSmiley 3 · 0 1

Use the formular for solving quadratic equation.

x = (3+sq root (9+32))/4 or
x = (3-sq root (9+32))/4

Pse compute the answer yourself.

2007-03-23 10:22:01 · answer #5 · answered by Kenche L 2 · 1 1

You have to use the quadratic formula:
x=-b±√b^2-4ac/2a
a=2,b=-3,c=-4
x=(3±√(-3)^2-4(2*-4))/2(2)
x=(3±√9+32)/4
x=(3±√41)/4
x=-.85 or 2.35

2007-03-23 11:19:51 · answer #6 · answered by Anonymous · 0 1

2x² - 3x - 4 = 0
x = [3 ± √(9 + 32)] / 4
x = [ 3 ± √(41) ] / 4
x = 2.35, - 0.85

2007-03-23 10:24:48 · answer #7 · answered by Como 7 · 1 1

I believe that it is no solution... i can't get it to factor

2007-03-23 10:25:30 · answer #8 · answered by absolution0408 2 · 1 1

this is a wrong equation.

2007-03-23 10:24:06 · answer #9 · answered by creagrouption 1 · 0 2

fedest.com, questions and answers