Please i need help theres another question thats hard????//?

Question

In a triangle, the base is 3cm less than the height. if the area is 14cm(to the power of 2),find the height of this triangle?


thanks for the previous answer u dont know how much u helped me guys thanks

Answer 1

let the base be B
height = B+3

B*(B+3)/2 = 14

b*(b+3) = 28
b*b + 3b - 28 = 0

Which is a quadratic equation (b+7)(b-4)= 0
roots (-7,4)
since base cannot be negative
base = 4
height = 7

Answer 2

b = h - 3

a = 1/2 * b * h = 14

14 = 1/2 * (h - 3) * h

28 = h^2 - 3h

h^2 - 3h -28 = 0

(h - 7)(h + 4) = 0

h = 7, -4

since it is a length, height must be 7

Answer 3

Assume that the base =x and height=y.
y-x=3...1
y=3+x.....2
1/2xy=14....3
xy=28......4

Put 2 into 4.
x(3+x)=28
3x+x^2-28=0
(x-4)(x+7)=0
x=4 @-7

Since length>0, x=4

xy=28
4y=28
y=7

I hope this helps. :)

Answer 4

the height is h..........base=b ......... area=14
b= h-3 ..............(1)
0.5bh= 14
=> 0.5(h-3)h=14
(h^2)/2 - (3/2)h= 14
h^2-3h-28=0
(h-7)(h+4)= 0
h=7 , h= -4
then h= 7

I advice you to think more and turn your mind on.
because your Qs r too easy and u can solve them.