2007-03-23 02:19:29 · 21 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
One no. = x
2nd no.= x+1
3rd no.= x+2
When we add:
x+x+1+x+2=6
3x+3=6
3x=6-3
3x= 3
x = 3/3
x = 1
So,
Ist no.= 1
2nd no.=2
3rd no.=3
So, You found out what is x. Now multiply these numbers, you will get 6 as answer.
2007-03-23 03:07:43 · answer #1 · answered by hyder_pillai 2 · 0⤊ 0⤋
1, 2 and 3
2007-03-23 02:22:49 · answer #2 · answered by shilpu 2 · 0⤊ 0⤋
3 2 1
3*2*1=6
3+2+1=6
2007-03-23 02:22:12 · answer #3 · answered by Anonymous · 0⤊ 1⤋
1, 2, and 3 1+2+3=6 1*2*3=6
2007-03-23 02:22:02 · answer #4 · answered by Anonymous · 0⤊ 1⤋
the numbers are 1, 2, 3
1+2+3 = 6
1*2*3 = 6
2007-03-23 17:11:56 · answer #5 · answered by sreedevi a 2 · 0⤊ 0⤋
1, 2, 3
2007-03-23 04:01:40 · answer #6 · answered by maverick_youth 4 · 0⤊ 0⤋
1, 2, 3
2007-03-23 02:22:07 · answer #7 · answered by sunny 3 · 0⤊ 1⤋
1, 2, & 3
2007-03-23 02:21:45 · answer #8 · answered by mikedotcom 5 · 0⤊ 1⤋
1, 2, 3,
1+2+3 =6
1× 2 × 3= 6
2007-03-23 02:21:28 · answer #9 · answered by Pranil 7 · 0⤊ 1⤋
There is an infinite number of solutions to the problem
x+y+z = xyz = 6.
If I take z = 1.5, then I have
x+y = 4.5 and xy = 4
→ x(4.5-x) = 4
→ x² - 4.5x + 4 = 0
→ x = [4.5 ± sqrt(20.25 - 16)] 2 = (9 ± sqrt(17)) / 4.
So the numbers 1.5, (9 + sqrt(17)) / 4 and (9 - sqrt(17)) / 4 will also work.
2007-03-23 03:27:27 · answer #10 · answered by Anonymous · 2⤊ 0⤋