2007-03-23 00:28:38 · 4 answers · asked by R2D2 1 in Science & Mathematics ➔ Mathematics
Please put some spaces in your equation so that we can see it all. That usually gets rid of the dots.
2007-03-23 00:32:17 · answer #1 · answered by Anonymous · 0⤊ 0⤋
It is tee because 3^x+5=9^x 5+3=8+x=10
2007-03-23 07:33:51 · answer #2 · answered by nicky66667 2 · 0⤊ 0⤋
10
2007-03-23 08:23:03 · answer #3 · answered by Anonymous · 0⤊ 1⤋
3^x + 5 = 9^x = (3^2)^x = (3^x)^2
Let y = 3^x
Therefore, y + 5 = y^2
or, y^2 - y - 5 = 0
Solve using quadratic formula :
y = [1 ± sqrt(21)] / 2
But y = 3^x can never be negative, so the
only solution is y = 3^x = [1 + sqrt(21)] / 2
Using logarithms :
x = log{[1 + sqrt(21)] / 2} / log(3)
That's the exact solution.
0.93436337... is the approximate solution.
2007-03-23 08:32:14 · answer #4 · answered by falzoon 7 · 1⤊ 0⤋