can you solve this equation please x2-1=0 thanks?

Question

it actually x squared - 1 = 0

Answer 1

x^2 -1 = 0
adding ont to both
x^2 = 1
square root both
( don't forget + or - root )
x = +1 or -1
snother solution
factor
(x-1)(x+1)=0
eithrer x-1 = 0
x = 1
or x+1 = 0
x = -1
solution 1 , -1
hope that helps

Answer 2

X^2=1 ==> X=-1 OR X=1

Answer 3

X^2-1=0 ; X^2=1 the result X1 = 1 ' X2 =-1

Answer 4

X square -1 =0
(x-1)(x+1)
x-1 =0 and x+1=0
x= 1 and x= -1

Answer 5

x² -1 = 0 » x² = 1 »» x = \/1 » x' =1 ; x'' = -1

Answer 6

ok, so x^2 - 1 = 0 so we need to make x the subject which means get to make x= ....

so lets start, we can move the minus one to the ohter side so when you move over the equal sign the sign changes and becomes the opposite so the opposite sign of minus is plus.

x^2=0+1

x^2=1

remeber when the x is squared then we do the root and when its the root we do square.

so here the x is squared so we root the 1
so root sign 1 is 1 or -1 because remeber when square -1 its 1.

so the answer is x=1 or -1

so now lets check:

if x=1 then substitute it with x so its 1squared = 1^2 which is 1

so 1-1=0

if x=-1 then substitute it with x so its 1squared = -1^2 which is 1

so 1-1=0

so our answer is right.

Answer 7

*you should use the Quadratic Equation. The Quad equation is x = [- b + /- V`(b^2 - 4ac)] / 2a *observe (V` represents an intensive sign/sq. root) First: be sure the "a", "b", and "c" variables >>> a = 3, b = 5, and c = a million Sec: place the coefficients interior the quad equation > x = [- 5 +/- V`(5^2 - 4(3)(a million)] / 2(3) x = [- 5 +/- V`(25 - 12) / 6 x = [- 5 +/- V`13] / 6 third: you will have 2 separate equations, one with addition and the different with subtraction. a million. x = [- 5 + V`13] / 6 x = -5/6 + (V`13)/6 2. x = [- 5 + V`13] / 6 x = - 5/6 - (V`13)/6

Answer 8

x^2=1
x=square root of 1 which equals 1

Answer 9

x squared - 1 = 0

x squared = 1

square root of (x squared) = square root of 1

x = 1 (because the square root of 1 is still 1)

Answer 10

2(square)
x - 1 =0

x^=1
x = 1 because x square is equal to ( 1 * 1) one, so x is 1.