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a runaway truck with failed brakes is moving downgrade at 102 km/h just before the driver steers the truck up a frictionless emergency escape ramp with an inclination of = 10°. The truck's mass is 1.2 x 104 kg. (a) What minimum length L must the ramp have if the truck is to stop (momentarily) along it? (Assume the truck is a particle). What is the minimum length L if (b) the truck's mass is decreased by 21% and (c) its speed is decreased by 34%?

thanks very much

2007-03-22 22:28:17 · 4 answers · asked by Wilson J 4 in Science & Mathematics Physics

4 answers

v = 102 * 3600/1000 metres/second

Conservation of energy: when it reaches a stop all the kinetic energy (m*v^2/2) will have been converted to potential energy (m*g*h)

Find h (the vertical height gained) then length of the ramp L is just h/sin(10)

Not his day is it? Brakes failed and some nut designs a frictionless escape ramp!

2007-03-22 23:19:03 · answer #1 · answered by lunchtime_browser 7 · 1 0

The truck is moving horizontally as it approaches the slope, and parallel to it, when it is on the slope. It is motion parallel to the slope with which you are concerned. The acceleration due to gravity, g, may be considered to have a component acting perpendicular to the slope, and a component acting parallel to the slope. From trigonometry, the component of g acting down a slope of angle 'z', = g(sin z). So, where z is 10 degrees, sine of z = sine of 10 = 0.174
So, if g = 9.8 ms^-2, gsinz = 9.8 x 0.174 = 1.7 ms^-2.

This can then be used as the value 'a', the acceleration, in the equation, v^2 = u^2 + 2as,
where v = final velocity (0, since the truck comes to a stop).
u = intitial velocity (102 km/h = 28.3 ms^-1)
a = gsinz = 1.7 ms^-2. Actually, -1.7 ms^-2, because this is decelleration, not acceleration)
s = L, the distance tavelled.

Substitute in these numbers gives:
0 = 28.3^2 + 2 x (-1.7) x L
Simplify and rearrange:
802.8 = 3.4L, therefore:
L = 802.8/3.4 = 236.1 m.

b). The force of gravity acts in proportion to the mass of the object, so altering its mass will have no effect. (Just as a cannon ball and a tennis ball fall at the same rate).

c) Decreasing its speed by 34% gives it a new speed of
0.66 x 28.3 = 18.7 ms^-2. Use this as the value of 'u' in the equation above, to solve this question.

2007-03-22 23:33:18 · answer #2 · answered by Ian I 4 · 1 0

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2007-03-22 23:13:06 · answer #3 · answered by Byzantino 7 · 0 0

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2016-10-19 09:59:41 · answer #4 · answered by scafuri 4 · 0 0

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