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A position function of a particle is given by
s=t^3 - 6t^2 + 9t +1, t is greater than or equal to 0
Find the velocity after 4 s.

I tried taking the derivative of s and got 3t^2 - 12t + 9 however when I substituted t for 4 and got 33 m/s, the answer key said it was 9 m/s. Whats going on? What makes this question different from your "average" calculus velocity question?

2007-03-22 17:44:35 · 2 answers · asked by ellen z 1 in Science & Mathematics Mathematics

2 answers

3*(4)^2-12(4)+9=
48-48+9=
9 m/s
I believe your substitution is incorrect.

2007-03-22 17:52:59 · answer #1 · answered by Nicknamr 3 · 0 0

Check your math when you substituted t = 4 in your velocity equation.

3(16) - 12 (4) + 9 = 9 , not 33

2007-03-23 00:55:07 · answer #2 · answered by yup5 2 · 0 0

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