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slope= -1.10x10^4 K
y-int=33.5
k has units of s^-1
the temperature varies through each experiment, but is not given
based on a ln(k) versus 1/T plot

2007-03-22 17:25:59 · 1 answers · asked by uber420racer 1 in Science & Mathematics Chemistry

1 answers

ln k = ln ko - (Ea/R) 1/T

If you are sure, the slope of this is known, it is equal to Ea/R.
Ea: activation energy, R: gas constant.
Make sure T (temperature) is in Kelvins.
Make sure the units are consistent.

2007-03-22 18:58:21 · answer #1 · answered by iuelph 1 · 0 0

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