2007-03-22 16:57:00 · 8 answers · asked by andrewcountryboy 1 in Beauty & Style ➔ Fashion & Accessories
That's impossible. First of all, prescriptions are given in diopters (like -2.25, +4.50) so you wouldn't know which ones to get. Second of all, even if someone were selling their old glasses online, that doesn't mean you would be able to see out of them. When you get glasses, the optician takes measurements to check the segment height, and other info from your eye so that you can see out of the lense properly. So in short, just go to walmart or jcpenney's where you can get it for cheap.
2007-03-23 09:35:03 · answer #1 · answered by Supergirl 2 · 0⤊ 0⤋
By the time you pay for shipping for them online, they won't be cheap. You would be better taking a prescription from your eye doctor to a store like Walmart or Shopko and getting a cheap pair. It would run you around $40.-$50. and they would fit your face properly and be the correct prescription for your eyes.
2007-03-23 00:14:13 · answer #2 · answered by tabby1002 1 · 0⤊ 0⤋
I wouldn't buy used glasses. I have been wearing glasses most of my life, and I always go to my eye doctor anually to have my eyes tested, and if I need a new presciption I wlll buy new glasses, because my insurance pays for most ot the bill. This past fall I got myself a new pair of glasses and I really like them.
2007-03-23 00:51:32 · answer #3 · answered by Pauly W 7 · 0⤊ 0⤋
why do u want a used pair of glasses...u should go to the eye doctor...
but since thats your request: try EBAY
2007-03-23 00:01:20 · answer #4 · answered by pink_peas624 3 · 0⤊ 0⤋
go to a doctor and get a prescription. don't go online shopping for something like that.
2007-03-23 00:23:43 · answer #5 · answered by Anonymous · 0⤊ 0⤋
Go to the doctor. Its what's best for your eyes. Best advice.
2007-03-23 00:17:21 · answer #6 · answered by Nikki 2 · 0⤊ 0⤋
how much is 20/40? like 4.0, 5.0???
2007-03-23 00:10:27 · answer #7 · answered by chikis*trikis 5 · 0⤊ 0⤋
ebay
2007-03-23 00:17:10 · answer #8 · answered by Anonymous · 0⤊ 0⤋