2007-03-22 16:50:46 · 9 answers · asked by Anonymous in Science & Mathematics ➔ Physics
Assuming the cannon that fired the cannonball is completely horizontal to the plane and that the ball does not spin, then they would hit the ground at the same time.
2007-03-22 16:53:57 · answer #1 · answered by Anonymous · 1⤊ 0⤋
If the cannot is fired horizontally, then in theory, both balls will reach the ground at the same time.
If you drop the cannon ball from the top of the World Trade Center 1, 2, or 7 on 9/11/2001, then the building may collapse and completely disintegrate before the cannon ball reaches the ground. (That's a joke)
2007-03-22 17:24:24 · answer #2 · answered by Skeptic 7 · 0⤊ 3⤋
Not enough info...
Assuming the canon firing the ball at a positive angle and the other ball drops from the same height as the cannon....
I would say the one dropped would hit the ground first....the ball being fired from the cannon needs to travel in a negative parabola shape first, maximize then drop....
If the cannon fires the ball horizontally, I would say the ball dropped at the same height would still beat it to the ground below....forward movement would impede the fired ball's drop....
If fired downward....you get the picture....
2007-03-22 17:39:39 · answer #3 · answered by tito_swave 4 · 0⤊ 2⤋
If you think of it as a simple work of component vectors, gravity (the lone force acting upon the cannonballs after being released from the cannon and the hands, assuming air resistance is negligible) works with the same force in the same direction on both cannonballs. Just remember that gravity is the ONLY force acting upon the cannonballs, and it is identical to both cannonballs. The horizontal momentum is not being increased by the presence of another force (unless its like a rocket powered cannonball or something, some bs like that) so the balls drop at the same rate from the same height and hit the ground at the same time. i love you.
2007-03-22 17:03:46 · answer #4 · answered by Anonymous · 0⤊ 1⤋
If you are firing a cannon, let's say, up into the air, normal cannon projectile, you are firing it so that it *does not* hit the ground for a while, presumably until it reaches enemy lines. A cannon is going to be, oh, say two-three feet off the ground. It might fly several hundred yards. If you hold a cannon ball two-three feet off the ground and then... let go --you figure it out from there.
2007-03-22 17:07:42 · answer #5 · answered by Chotu B 2 · 0⤊ 2⤋
Cannonball Drop
2016-12-11 14:41:13 · answer #6 · answered by Anonymous · 0⤊ 0⤋
The first answer is correct but he didn't say why...the reason gravity is working the same on both canon balls so they would hit at the same time
It is like shooting an arrow at a monkey in a tree and the monkey drops at the same moment the arrow is released. the arrow will hit the monkey because the same gravity is working on the monkey as is the arrow.
It doesn't sound logical but that is the truth
2007-03-22 16:59:24 · answer #7 · answered by pinelake302 6 · 0⤊ 1⤋
the same time, if you drop the one in your hand at the exact time the second one exits the cannon barrel (is not touching the barrel) The barrel must be parallel to the ground and not pointed up or down
2007-03-22 17:02:29 · answer #8 · answered by jimmy 1 · 0⤊ 1⤋
umm this question doesnt make sense since how can you drop something from the same height as something being fired? see one is falling and one is being shot out of something, nothing to compair
2007-03-22 16:54:25 · answer #9 · answered by laura n 3 · 0⤊ 4⤋