Convert to algebraic expression?

Question

9 times a number divided by 5 is 18

Answer 1

Let the number be N,

9 times a number,

9 x N

divided by 5 is 18

(9 x N) / 5 = 18

Answer 2

9*n/5 = 18

Answer 3

9(n/5)=18

Answer 4

Let x be the number, then
9x/5 = 18

Answer 5

9 * x /5 = 18
9x/5 = 18

Answer 6

what's the complicated section?! purely "convert" each and each operator in the type utilized by using the language; e.g. multiplication is often *, branch (fractions are divisions) with / .. etc... the different concern to care of is the operations order; follows the regulations of math and "combine" them with that of the language in use, tipically they "imitate" the maths ones. so: look into the expression: there's a brilliant fraction between a numerator N and denominator D, so first your expression is f = (N) / (D); we've written () to be sure of the splendid order of computation even while we will "boost" N and D. now enable's do it, enable's boost N first N is two * (p/q)^(ok-a million) that's common for languages that have ^ (others use **, others pow .......) it extremely works in view that operator priority is what we predict in maximum languages. in case it is not any longer, we could continuously upload a () like 2 * ( (p/q)^(ok-a million) ) this (or prev one) is N and we can replace it in our "form" f = (N) / (D); the () around ok-a million mandatory in view that we could delimit the exp, or the translation would be A^ok - a million (the exp being ok on my own). without () around p/q, it could be examine as p/(q^(ok-a million)), i.e. a fragment the place numerator is p, denominator is q^(ok-a million), this is faulty for us D (denominator) is in an analogous way "created" following the maths expression (r - 3*t)^(a million/m) and right here too there is not any ask your self. replace rather of D and you have your f. observe: many langs while coping with floating element costants want that's explicitly given; so numbers like 3 could become 3.0 extra wisely; others would "forged" intergers to floating element "automatcally" even with the undeniable fact that it relies upon on the form of vars like m or t... e.g. if m is integer, a language could compute a million/m as integer branch, and beneficial it yields 0 (for m>a million) ... if we are saying a million.0 rather, we tension a floating element branch, this is probable what we would have enjoyed. conventions would variety slightly in accordance to the language, yet truthfully many shares the comparable techniques.

Answer 7

9x/5 =18
9x=90
x=10

Answer 8

9X / 5 = 18
9X = 90
X = 10

Answer 9

(9x)/5=18

x=10