You read correctly. In this case, the group operation is function composition, so we need to find the results of applying the permutation f=(123) repeatedly.
f⁰({1, 2, 3}) = {1, 2, 3}
f¹({1, 2, 3}) = {3, 1, 2}
f²({1, 2, 3}) = {2, 3, 1}
f³({1, 2, 3}) = {1, 2, 3}
After that the cycle repeats, so the elements of the group are f⁰, f¹, and f², which are the permutations (), (123), and (132), respectively.
2007-03-22 16:44:28
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answer #1
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answered by Pascal 7
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You were just having a minor brain cramp.
A permutation isn't a group. :)
2007-03-23 09:05:57
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answer #2
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answered by Curt Monash 7
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