A mixture of 6.20 g of O2 and 11.4 g of Xe exerts a pressure of 0.460 atm.?

Question

What is the partial pressure, in atm, of the O2 gas ?

Answer 1

Without grinding through the numbers, divide 6.2 by 32 to get the moles of O2 and 11.4 by the atomic weight of Xe to get the moles of Xe. The partial pressure of O2 will be
moles O2/ total moles x 0.46 atm.