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solve the inequality and indicate the solution set.

2x-3 > -12 or 2x-1<-1

2007-03-22 16:05:19 · 5 answers · asked by Orange? 4 in Science & Mathematics Mathematics

5 answers

1) 2x-3 > -12
add 3 to both sides ...2x>-9
divide by 2... x>-9/2
2) 2x-1<-1
add 1 to both sides... 2x<0
divide by 2 ...x<0
so x is larger than -9/2 and smaller than 0
therefore the interval for x; -9/2

2007-03-22 16:11:38 · answer #1 · answered by Birim 3 · 1 0

x>9/2 or x<0

2007-03-22 23:16:09 · answer #2 · answered by Justina 3 · 0 0

First, because the two inequalities are linked by OR, we are looking for the places where one or both of the inequalities are true.

2x-3 > -12
2x > -9
x > -4.5

2x-1<-1
2x <0
x<0

Draw a numberline on your paper if it helps you visualize.

For x>-4.5, shade right of -4.5 with an open circle on -4.5
For x<0, shade left of 0 with an open circle on 0.

Notice that the shadings intersect and cover the whole numberline. Thus the solution is all values of x

2007-03-22 23:12:36 · answer #3 · answered by Anonymous · 1 1

x is greater than -9/2 or x is less than 0

2007-03-22 23:09:56 · answer #4 · answered by mochachocolata 3 · 0 0

2x-3>-12 or 2x-1<-1
2x>-12+3 2x<0
2x>-9 x<0
x>-4.5

-4.5

2007-03-22 23:15:44 · answer #5 · answered by william_kah83 1 · 0 1

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