Why?
2007-03-22 15:50:02 · 14 answers · asked by White 7 in Entertainment & Music ➔ Polls & Surveys
Lol...this was categorized as "Fast Food"...I wonder why?
2007-03-22 15:50:27 · update #1
The tasty little morsel of a dog in dark sunglasses. I'd probably have an accident on the carpet.
2007-03-22 16:00:51 · answer #1 · answered by comet girl...DUCK! 6 · 2⤊ 0⤋
The panda will misbehave first, they think cuteness will let them get way with anything whereas a white lioness is always a regal lady.
2007-03-22 22:59:36 · answer #2 · answered by flipper069 3 · 1⤊ 0⤋
Umm I would expect the lioness to misbehave
chancer are she would eat the panda ,but then again depends on what's for dinner .Oh I give up!
2007-03-22 22:59:23 · answer #3 · answered by selma b 4 · 1⤊ 0⤋
It depends. . .if the lioness and the panda arrived at the same time, the lioness.
If the lioness arrived first, and sampled the delicious hors douerves, then the panda.
My money's still on the lioness.
2007-03-22 23:47:34 · answer #4 · answered by Veruca Salt 6 · 1⤊ 0⤋
I expect the panda to misbehave first...even if it wasn't angry. As Innocent as they may look, it isn't true! I've seen a bad panda plenty of times...
2007-03-22 22:56:49 · answer #5 · answered by Rocky 3 · 1⤊ 0⤋
The only white lioness I know is a perfect lady unless she's annoyed, and then she retains her class and cool, so it's gotta be the panda!
2007-03-23 13:00:06 · answer #6 · answered by Baby'sMom 7 · 1⤊ 0⤋
The angry panda will definitely misbehave first. I've already had it happen one time and I know it will happen again.
2007-03-22 22:58:23 · answer #7 · answered by Anonymous · 1⤊ 0⤋
neither would misbehave first...I would because I have been extremly abnoxcious lately
AND I WOULDN'T EVEN INVITE A PANDA OR A LOIN TO DINNER IN THE FIRST PLACE lol
2007-03-22 23:08:13 · answer #8 · answered by Anonymous · 1⤊ 0⤋
The panda and I agree, eat the panda.
2007-03-22 23:00:04 · answer #9 · answered by Anonymous · 1⤊ 0⤋
the angry panda
2007-03-22 22:53:42 · answer #10 · answered by Seed of giggles 3 · 1⤊ 0⤋