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vertical. If the motorcyclist negotiates the curve without sliding, her speed is

2007-03-22 12:20:36 · 2 answers · asked by l_walker2005 1 in Science & Mathematics Physics

2 answers

Here,
angle = 10 degree
radius, r = 30m
gravitational acceleration, g = 9.8 m/s&2
velocity, v = ?

we know,
tan10 = v^2/rg
or, v = ( rg * tan10) ^ .5
or, v = ( 30 * 9.8 * tan 10 ) * .5
so, v = 7.2 m/s

The speed of the motorcycle is 7.2 m/s (ans.)

Hope this was helpful.

2007-03-22 18:18:35 · answer #1 · answered by rhapsody 4 · 0 0

This is sort of an odd problem, so I'm not certain of my solution

I think it has to be approached at a torque problem.

Take the axis of rotation to be where the road meets the tires.

mglSin[80º]=(mv²/r)Sin[10º]l

Cancel the mass and the l term and solve for the speed.

2007-03-23 00:59:27 · answer #2 · answered by 2 meter man 3 · 0 0

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