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A 10.0-mL sample of 0.75 M CH3CH2COOH is titrated with 0.30 M NaOH. What is the pH of the solution after 22.0 mL of NaOH have been added to the acid? Ka = 1.3 × 10-5
5.75
4.94
4.83
4.02
3.95

2007-03-22 10:28:35 · 1 answers · asked by jennifer 2 in Science & Mathematics Chemistry

1 answers

the answer is 5.75
you can find the mole of CH3CH2COOH and NaOH
then take acid react with water, write Ka expression,
remember V= 32ml
find the concentration
easy to have answer

2007-03-22 14:54:15 · answer #1 · answered by Helper 6 · 0 0

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