Find the Work?

Question

The net force acting on a 6.0-kg object is given by Fx = (10 - x) N, where Fx is in newtons and x is in meters. How much work is done on the object as it moves from x = 0 to x = 10 m?

Answer 1

Work done dW= F dx

dW = (10 - x) dx

total work done

W = ∫ (10 - x) dx in limits

W = 10 x - 0.5 x^2 in limits

W = [10 *10 - 0.5*100] - [10 *0 - 0.5*0]

W = 100 - 50 = 50 N-meter

mass could be used if given Fx is acceleration.