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If I have a cyclinder with a diameter of 2.75", what would a proportional cylinders' diameter be if it could hold 8 times the volume? Please explain mathmaticaly....thanks

2007-03-22 03:23:58 · 6 answers · asked by brent a 1 in Science & Mathematics Mathematics

6 answers

New diameter = 5.5"

If you have a solid of volume V, and increase it proportionally so that some linear measurement (such as the diameter or height) increases from d to a*d, the volume will increase by a^3*d. Since the volume increases by a factor of 8, each linear measurement will increase by a factor of the cube root of 8, which is 2. Thus the new diameter is 2*2.75" = 5.5".

2007-03-22 03:31:13 · answer #1 · answered by Michel_le_Logique 4 · 0 1

Volume of a cylinder (V) = Length (L) * pi * radius (r)^2

V= L * pi * r^2
V= L * pi * (1.375^2)
V= L * pi * (1.890625)

Now, multiply each side by 8, o get 8 times the volume (NOTE: This is assuming that the Length of the cylinder DOES NOT change.)

8V= L * pi * (1.890625) (8)
8V= L * pi * (15.125)

Get the square root of 15.125 to get the radius, and then multiply that number by 2 to get the new diameter

square root of 15.125 = 3.889

Diameter = 7.778"

2007-03-22 10:44:55 · answer #2 · answered by LaTiNoFiNo 2 · 2 1

pi (d/2)^2 h = V (8)

d^2/4 = 8V/ pi h

d = sqrt 32V / pi h

Since neither your volume or height are limited you have an infinite number of possibilities for the diameter, only as long as the above equation is satisfied.

2007-03-22 10:30:09 · answer #3 · answered by piri82 3 · 0 2

it should have a diameter of 5.5" as the volume is proportional to the cube of the radius/diameter

2007-03-22 12:36:09 · answer #4 · answered by raj 7 · 1 1

Volume = π x r x r x h
.... Let h = 1
3.142 x 1.375 x 1.375 x 1 = 5.940 x 1
New volume = 8 x 5.940 = 47.523in³
√47.523 ÷ 3.142 = 3.9" radius x 2 = 7.8" diameter.

2007-03-22 11:51:26 · answer #5 · answered by Norrie 7 · 1 1

To calculate volume you need the height of the cylinder

2007-03-22 10:27:39 · answer #6 · answered by kp45ca 1 · 0 2

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