The measurement of the sides of the triangle are 8 inches, 9 inches, and 10 inches. Is this triangle a right triangle? Why or why not?
2007-03-22 03:13:34 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
c² = a² + b²
(10)² = (8)² + (9)²
100 = 64 + 81
100 = 145
The two sides must equal the third side (Hypotenuse). in this case 100 the hypotenuse is less than 145. Therefore this is not a right triangle.
- - - - - - - -s-
2007-03-22 03:47:30 · answer #1 · answered by SAMUEL D 7 · 0⤊ 0⤋
No.
In order to be a right triangle, it must meet the restrictions of the pythagorean theorem, that a^2 + b^2 = c^2.
A is the length of one side, B is the length of another, and C is the length of the hypotenuse. The hypotenuse is the longest side of a right triangle, and is always across the triangle from the 90-degree angle.
So let's see if this triangle passes the test:
If this is a right triangle, then 8^2 + 9^2 =10^2.
64+81 = 100
Ummm...no.
So, this is not a right triangle.
2007-03-22 03:23:51 · answer #2 · answered by Brian L 7 · 1⤊ 0⤋
Right triangles exhibit the property that the square of the hypotenuse (the long side) is equal to the sum of the squares of the other two sides. In this case SQRT(8^2+9^2)=12.04, not 10. Therefore this is not a right triangle.
2007-03-22 03:28:43 · answer #3 · answered by jsb5391 1 · 0⤊ 0⤋
By the pythagoras theorem, 8^2 + 9^2 is 145, not 10^2 as in your case. Therefore, it is not a right-angled triangle.
2007-03-22 03:21:42 · answer #4 · answered by sky_blue 1 · 1⤊ 0⤋
no ...
in a right triangle, pythag theorem says:
a^2 + b^2 = c^2 where "c" is the long side (hypoteneuse)
8^2 + 9^2 = 64 + 81 = 145
but 10^2 = 100
2007-03-22 03:17:32 · answer #5 · answered by atheistforthebirthofjesus 6 · 2⤊ 0⤋
No.
8^2 + 9^2 isn't 10^2.
2007-03-22 03:18:53 · answer #6 · answered by Mark H 3 · 1⤊ 0⤋