English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

You've got to draw a square with a cross in the middle (two diagonal lines). You're not allowed to take ya pen off the paper or go draw over the same line.

How do you do this again?

Hope that makes sense. Explain as best ya can please. Ta.

2007-03-22 03:05:20 · 6 answers · asked by Sluugy 5 in Science & Mathematics Mathematics

6 answers

ive tried it and thats impossible to do

2007-03-23 07:52:58 · answer #1 · answered by Frihah Anti-Milanist 4lyf! 6 · 1 0

Does not sound possible, at least on a normal piece of paper. Each corner of your square has three lines that must be drawn. You can draw the three lines in the corner you start from and the corner you end with, but you can't draw the other two corners.

You could draw an envelope shape, with a "flap" extending outside one side of the square. In that case, you would could draw the shape by starting at, say, the lower left corner. Draw in to the center, back out to the other bottom corner, across the bottom, up to top of square, then down to the center again, up to the other to corner, across to the first top corner, then draw the flap back to the other top corner, then down to the bottom again, completing the shape.

2007-03-22 10:23:02 · answer #2 · answered by NotEasilyFooled 5 · 0 0

Can't be done. The diagram you describe is a square with diagonals, so it has more than two vertices (corners) with an odd number of lines coming from them.

You can only draw diagrams where each vertex has an even number of lines coming from it, or where exactly two vertices have an odd number of lines. In this latter case, you have to start drawing at one of the odd vertices and end at the other.

Think of it... with an even vertex, you can start somwhere else, enter the vertex, and then exit the vertex. If you have an odd vertex, and you don't start there, you *have* to end there - because when you draw the last line in there, you can't go any further. This makes it impossible to draw a diagram with more than two odd vertices.

2007-03-22 10:15:06 · answer #3 · answered by Bramblyspam 7 · 1 1

*5
* 4 *3

* 2 *1
The shape ends up something like this!
Start at No 1. Draw a line to No2.
From there go to 3, then to 4.
Up to 5 and back to 3.
Back down to 1, across to 4 and finish at 2.
Hope this helps!.

2007-03-22 10:36:11 · answer #4 · answered by Old Man of Coniston!. 5 · 1 0

As long as you start from a point where an ODD number of lines meet then it's possible.It is impossible if you start at a point where an EVEN number of lines meet..try it!
The only two possible starting places are the bottom corners.
(If you've got a roof on it.)

2007-03-22 11:10:27 · answer #5 · answered by Anonymous · 0 0

we had a wee roof on ours? draw up, then diagonally to the lower left...then up again then across to original line then up to a triangle point....back down to complete triangle then diagonally down to the right then last line to complete the box....hope this helps!!!!!

2007-03-22 10:11:45 · answer #6 · answered by Anonymous · 0 0

fedest.com, questions and answers