The fott of the ladder is placed 3 feet from a building. The ladder is 7 feet long. How high does the ladder reach on the building?
2007-03-22 02:48:42 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Pythagorean Theorem
c² = a² + b²
c² - b² = a² . .Use this formula
± √(7)² - (3²) = √a²
± √49 - 9 = √a²
± √40 = √a²
6.32455532 feet = a
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2007-03-22 03:23:10 · answer #1 · answered by SAMUEL D 7 · 0⤊ 0⤋
Imagine a right angled triangle ABC.
let AB=hypotenuse=length of ladder=7 ft
let BC=base=distance of foot of ladder from building= 3 ft
let AC=perpendicular=height of ladder
using Pythagoras theorem,
AC=sqrt(AB^2 - BC^2)
=sqrt(7*7 - 3*3)
= sqrt(49-9)
= sqrt (40)
= 6.32 ft
Ans: Height of ladder is 6.32 feet.
2007-03-22 09:56:03 · answer #2 · answered by ? 5 · 0⤊ 0⤋
7 feet
2007-03-22 09:56:34 · answer #3 · answered by russgipson 2 · 0⤊ 0⤋
sqrt(7^2 - 3^2) = sqrt(49-9) = sqrt(40) = 2*sqrt(10) = 6.32455 ft.
2007-03-22 09:52:34 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Pythagorus theorem.
2007-03-22 09:54:34 · answer #5 · answered by Anonymous · 0⤊ 1⤋
Get a measuring tape and measure it.
2007-03-22 09:52:13 · answer #6 · answered by hotmama 4 · 0⤊ 0⤋
use Pythagoras theorem
6.3245 ft.
2007-03-22 09:56:25 · answer #7 · answered by tafi75 5 · 0⤊ 0⤋