Sara bikes 10 miles due east, and then 5 miles north. What is the shortest distance back to where she began?
2007-03-22 02:45:07 · 13 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
OK!
This is a right triangle problem.
Use the Pythagorean Theorem.
10^2 + 5^2 = C^2
125 = C^2
11.2 = C (about)
2007-03-22 02:46:54 · answer #1 · answered by Jerry P 6 · 0⤊ 0⤋
The shortest distance must be the straightest line from the end point back to the starting point. Use Pythagorus theorem.
10^2 + 5^2 = x^2
100 + 25 = x^2
125 = x^2
x = (125)^1/2
x = 11.180339887498948482045868343656 miles
2007-03-22 09:51:56 · answer #2 · answered by Anonymous · 0⤊ 0⤋
A:start point
B:point at 10 miles due E
C:point at 5 miles N after B
The shortest distance back to A is the straight line AC, because BC+BA>AC
Then apply AB^2 + BC^2=AC^2 to this triangle, we have:
AC= sqrt (AB^2 + AC^2)
AC= sqrt (100 + 25)
AC= sqrt (125)=5sqrt5
2007-03-22 09:57:33 · answer #3 · answered by Candy 2 · 0⤊ 0⤋
Hi! It's about 11.2 miles in a south south westerly direction
2007-03-22 09:58:34 · answer #4 · answered by ray trigg 1 · 0⤊ 0⤋
The answer is 11.18 miles .Use the pythogorean theorem.Hypotenuse =square root of the sum of the square of the two sides.
2007-03-22 09:53:24 · answer #5 · answered by kp45ca 1 · 0⤊ 0⤋
sqrt(10^2 + 5^2) = sqrt(125) = 11.18
2007-03-22 09:48:40 · answer #6 · answered by Anonymous · 0⤊ 0⤋
A straight line from point C to point A.
2007-03-22 09:49:48 · answer #7 · answered by hotmama 4 · 0⤊ 0⤋
Find the hypotenuse of the triangle. Draw it out - it'll be obvious.
2007-03-22 09:47:58 · answer #8 · answered by poohb2878 6 · 0⤊ 0⤋
you've got your answer in the earlier answers.
2007-03-22 10:01:04 · answer #9 · answered by sanjay 4 · 0⤊ 0⤋
you lost me at problem
2007-03-22 09:52:05 · answer #10 · answered by Bluemahmed 2 · 0⤊ 0⤋