In a 100m race A can beat B by 5m and B can beat C by 10m.By how much distance can A beat C in the race
2007-03-22 02:34:51 · 5 answers · asked by bhargavi 2 in Science & Mathematics ➔ Mathematics
14.5m
Lets say A does it in 1 min. Thats 100m/min
B runs 95m in that time. Thats 95m/min.
So B runs 100m in 100/95 or 20/19 min.
C runs 90m in that time, or 90m/(20/19)min = 85.5m/min
So when A runs the 100m in one minute, C runs 85.5m.
So A beats him by 14.5 m.
OR, you can look at it this way:
Assume they all race together.
When A finishes, B is at 95 m.
But B's lead over C here is not 10m yet, since B hasn't finished the race, only 95% of it.
Therefore, B's lead over C at this point is 95% of 10 m, or 9.5 m.
Therefore A's lead over C is 5 + 9.5 = 14.5 m.
2007-03-22 02:39:25 · answer #1 · answered by Scott R 6 · 1⤊ 0⤋
IF a can beat B by 5m while B can beat C by 10 m,
this implies that A beats C by (5+(10-5)=) 10 m.
2007-03-22 02:39:46 · answer #2 · answered by ? 5 · 0⤊ 3⤋
Let x be the amount of time A needs for the race.
B runs 95 meters in x time.
Hence, B needs(100/95)*x to run 100 meters.
C runs 90 meters in (100/95)*x time.
Hence, C needs (100/90)*(100/95)*x to run 100 meters.
C runs 100 meters in 1.16959*x time
Hence, in x time, C runs (100/1.16959) = 85.5 meters
A beats C by 100 - 85.5 = 14.5 meters.
2007-03-22 02:43:24 · answer #3 · answered by Bramblyspam 7 · 0⤊ 0⤋
15
2007-03-22 02:37:17 · answer #4 · answered by metalluka 3 · 0⤊ 3⤋
A - B = 5
B - C = 10
A = 100
100 - B = 5
B = 95
95 - C = 10
C = 85
Therefore at the end of the race, when A has done 100m, C has done 85m.
100 - 85 = 15m (answer).
2007-03-22 02:38:38 · answer #5 · answered by cszoch 3 · 0⤊ 3⤋