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2007-03-22 01:27:43 · 3 answers · asked by Anonymous in Science & Mathematics Physics

...will have slower speed than the smaller skater.what is the principle behind this?(continuation)

2007-03-22 02:19:27 · update #1

3 answers

the larger one will not move as much.

It's conservation of momentum.

mass times velocities before = mass times velocities after.

So if you start with no momentum, you have to end with no net momentum.

So the chick skater (unless she's East German and has more mass) will fly off faster to have equal and opposite momentum to the guy's.

2007-03-22 01:33:31 · answer #1 · answered by Anonymous · 0 0

Conservation of momentum

Before the push, momentum = 0
After the push momentum is
M1V1 + M2V2 = 0
M1V1 = -M2V2

If M1 is larger than M2 than
V1 has to be smaller than V2 to respect the equality.

2007-03-22 08:50:09 · answer #2 · answered by catarthur 6 · 0 0

Will have what ?

2007-03-22 08:34:03 · answer #3 · answered by Gene 7 · 0 0

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