statistics help!! pleaseeee help me!?

Question

two standard 6-sided dice are rolled...
What is the probability of rolling a value larger than or equal to 7 given that each die lands on an even number?

Answer 1

There are 36 possibilities.

Since the result greater than 7 MUST have two EVEN numbers, the total of the dice MUST be even. The only EVEN results greater than 7 that can be rolled on two dice are 8, 10 and 12.

With ONLY EVEN numbers, 8, 10 and 12 can only be rolled in the following ways:

8:
4-4
6-2
2-6

10:
4-6
6-4

12:
6-6

The total number of these combinations is 6. Since there are 36 possibilities, the answer is that you will roll that combination (on average) 6 times out of every 36 rolls, or 6/36 which simplifies down to:

1/6

Hope this helped.

Answer 2

2 even integers cannot give u an odd integer
so 7 is out of question
+ 1 2 3 4 5 6
1 2 3 4 5 6 7
2 3 4 5 6 7 8
3 4 5 6 7 8 9
4 5 6 7 8 9 10
5 6 7 8 9 10 11
6 7 8 9 10 11 12
Ans 6/36

Answer 3

First thing is to consider what combinations of dice rolls will give you the condition you describe. There are six.

2 + 6
4 + 4
4 + 6
6 + 2
6 + 4
6 + 6

The probability of any one die ending up on one particular number is 1/6, so the probability of any two dice ending up on particular numbers is 1/6 * 1/6 = 1/36. So adding 1/36 to itself six times (for the six combinations found, above) gives you 6/36 = 1/6.

So the chances are one in six.

Answer 4

The odds of rolling a combination adding to 7 or greater with 2 dice is 21 in 36 or 58.333 % (probability of 0.58)

Not sure what you mean when you say "given each dice lands on an even number"

If you only accept dice combinations that contain at least one even number then the odds change to 18 combinations in 36 or 50% (0.5 probability)

If you require both dice to be even ..then your odds shift to 6 combinations in 36 or 16.66% (0.16)