check the API of substring carefully
it gives a substring from 3rd position to 8th position
2007-03-21 22:43:18
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answer #1
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answered by Anonymous
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1.public String substring(int beginIndex)
Returns a new string that is a substring of this string. The substring begins with the character at the specified index and extends to the end of this string.
Examples:
"unhappy".substring(2) returns "happy"
"Harbison".substring(3) returns "bison"
"emptiness".substring(9) returns "" (an empty string)
Parameters:
beginIndex - the beginning index, inclusive.
Returns:
the specified substring.
Throws:
IndexOutOfBoundsException - if beginIndex is negative or larger than the length of this String object.
2.public String substring(int beginIndex,
int endIndex)
Returns a new string that is a substring of this string. The substring begins at the specified beginIndex and extends to the character at index endIndex - 1. Thus the length of the substring is endIndex-beginIndex.
Examples:
"hamburger".substring(4, 8) returns "urge"
"smiles".substring(1, 5) returns "mile"
Parameters:
beginIndex - the beginning index, inclusive.
endIndex - the ending index, exclusive.
Returns:
the specified substring.
Throws:
IndexOutOfBoundsException - if the beginIndex is negative, or endIndex is larger than the length of this String object, or beginIndex is larger than endIndex.
2007-03-26 02:11:17
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answer #2
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answered by srihari_reddy_s 6
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b.substring(x,y)
x is the starting position in the string b (start counting from 0)
y is the length of the substring result
2007-03-22 05:43:02
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answer #3
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answered by abd 5
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First of all you need to tell us your desired output...
Take note the format of Date String
DDD MMM DD HH:MM:SS GMT+HH:MM YYYY
So if you want to take the time only
String a = b.substring(11, 20);
if you want the date MMM DD YYYY
String a = b.substring( 3, 9) + ", " + b.substring( 30, 34 );
/* GoOd LuCk */
2007-03-26 02:28:21
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answer #4
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answered by Liviawarty J 2
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hey visiy http://myjava.batcave.net
2007-03-22 10:06:13
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answer #5
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answered by Eranga D 2
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