smallest positive integer other than 1, which when devided by 2,3,4,5 always leaves a remainder of 1?

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2007-03-21 22:16:01 · 4 answers · asked by rai_chicks99 1 in Science & Mathematics ➔ Mathematics

let us find the LCM of the numbers
here LCM of 2 3 4 5 is 60
the smallest number to leave remainder 1 is (60+1)=61.

2007-03-21 22:51:05 · answer #1 · answered by satwik 2 · 0⤊ 0⤋

61.

I multiplied 3*4*5 to get 60, then added 1.
I didn't ignore the 2. If it's divisible by 4, it's divisble by 2.

2007-03-21 22:19:07 · answer #2 · answered by Anonymous · 0⤊ 0⤋

2,3,4,5

find the Lowest Common Multiple (LCM) which in this case is 60. To this add 1 ie 60+1 = 61

ans 61

2007-03-21 22:48:59 · answer #3 · answered by diamond 3 · 0⤊ 0⤋

Pick out the prime factors, multiply, and add 1.
2*2*3*5+1 = 61

2007-03-21 22:20:55 · answer #4 · answered by Captain Brock 4 · 0⤊ 0⤋