2007-03-21 21:57:11 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
x*(70-4x)*(56-2x)
(x*70-x*4x)*(56-2x)
70x*(56-2x)-4x^2*(56-2x)
70x*56-70x*2x
- 4x^2*56-4x^2*(-2x)
3920x-140x^2-224x^2+8x^3
3920x-364x^2+8x^3
Write the highest terms first:
8x^3-364x^2+3920x
Now check it. Is it right?
OK next time you can do your own homework!
2007-03-21 22:13:49 · answer #1 · answered by Captain Brock 4 · 0⤊ 0⤋
x ( 70 - 4x ) ( 56 - 2x ) =
x [ 2 ( 35 - 2x ) ] [ 2 ( 28 - x ) ] =
4x ( 35 - 2x ) ( 28 - x )
x = 0, x = 35/2, x = 28
2007-03-21 22:49:01 · answer #2 · answered by Zax 3 · 0⤊ 0⤋
best thing to do is break it out a little by extracting 2 from all inner numbers of parenthesis. making 2x(35-2x)(28-x). Can't simplify more than that. I thought u wanted to try and solve it also.
2007-03-21 22:05:00 · answer #3 · answered by niceguyswthrt 2 · 0⤊ 0⤋
x(70 - 4x)(56 - 2x) =
(70x - 4x²)(56 - 2x) =
3920x - 140x² - 224x² + 8x^3 =
3920x - 364x² + 8x^3
2007-03-21 22:08:39 · answer #4 · answered by Brenmore 5 · 0⤊ 0⤋
If you want to simplify that expression, my guess would be to expand the whole thing.
If you want the values of x, they are 0, 35/2, and 28.
2007-03-21 22:05:45 · answer #5 · answered by lamb.chops 2 · 0⤊ 0⤋
multiply x into (70-4x)= 70x-4x^2
then multiply (70x-4x^2) (56-2x)
(70x*56)+(70x*-2x)+(-4x^2*56)+(-4x^2*-2x)
3920x-140x^3-224x^2+8x^3
final ans:
-132x^3-224x^2+3920x
2007-03-21 22:04:41 · answer #6 · answered by siuchunzi813 1 · 0⤊ 0⤋
= x.(3920 - 140x - 224x + 8x²)
= x.(3920 - 364.x + 8.x²)
= 4x.(980 - 91.x + 2.x²)
= 4x.(2x - 35).(x - 28)
2007-03-21 23:58:42 · answer #7 · answered by Como 7 · 0⤊ 0⤋