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A=1/2h(b1 + b2) ; solve for b1

2007-03-21 20:31:06 · 3 answers · asked by clove83zm 3 in Science & Mathematics Mathematics

3 answers

1) A = (1/2h)(b1+b2)
2) A*2h = b1 + b2
3) A*2h - b2 = b1
4) b1 = 2Ah - b2

Hope this helps!!

2007-03-21 20:37:54 · answer #1 · answered by Imperial 2 · 0 0

now given no values for anything you need to get b1 alone on one side of equation. First multiply both sides by 2 to get rid of fraction giving you 2A = b1 + b2 and then subtract b2 from both sides. Gives you 2A - b2 = b1

2007-03-21 21:20:53 · answer #2 · answered by niceguyswthrt 2 · 0 0

A = ½h(b1 + b2) (x 2)
2A = h(b1 + b2) (÷ h)
2A/h = (b1 + b2) (- b2)
[2A/h] - b2 = b1

2007-03-21 22:23:07 · answer #3 · answered by Brenmore 5 · 0 0

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