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2007-03-21 20:07:41 · 16 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
x²+7x+12
2007-03-21 20:11:13 · answer #1 · answered by Rose 3 · 3⤊ 0⤋
(x + 3) ( x + 4 )
= x(x + 4) + 3(x + 4)
= x^2 + 4x + 3x + 12
= x^2 + 7x + 12
2007-03-21 20:14:40 · answer #2 · answered by rooster1981 4 · 0⤊ 0⤋
(x+3)(x+4)=x^2+4x+3x+12
=x^2+7x+12.
2007-03-21 20:11:51 · answer #3 · answered by musicloverboy88 2 · 0⤊ 0⤋
x^2 + 7x + 12
2007-03-21 20:15:16 · answer #4 · answered by Anonymous · 0⤊ 0⤋
x^2 + 7x + 12
2007-03-21 20:12:00 · answer #5 · answered by ashoke 2 · 0⤊ 0⤋
(X+3) (X+4)=?
NOW THIS CAN BE WRITTEN LIKE
(X+3)(X) +(X+3)(4)
NOW MULTIPLY
(X+3)(X)
YOU GET X^2+3X
NOW MULTIPLY
(X+3)(4)
YOU GET 4X+12
SO THE ANSWER IS X^2+7X+12
2007-03-21 20:32:24 · answer #6 · answered by Anonymous · 0⤊ 0⤋
x^2+4x+3x+12=X^2+7x+12
Therefore: (x+3)(x+4)= x^2 + 7x + 12
2007-03-21 20:15:24 · answer #7 · answered by reden 2 · 0⤊ 0⤋
= x² + 4x + 3x + 12
= x² + 7x + 12
2007-03-21 23:39:36 · answer #8 · answered by Como 7 · 0⤊ 0⤋
hi Its undemanding...:D as an occasion isnt 40 two - 40 two =0? it is reason 40 two is comparable to 2 .. so 2-2 =0 How do u do in "algebra" way?? reason they have a similar denomenator then you certainly merely placed the 1st 4 - the 2nd 4 over one denomenator it is two for this reason (4-4)2=02=0 persist with a similar element right here.... so u get ((x+4)-(x+a million))(x-3) = (x+4-x-a million)(x-3) =3(x-3) yet dont forget u try this in basic terms once you have comparable denomenator....!! Goodluck
2016-11-27 21:32:08 · answer #9 · answered by ? 4 · 0⤊ 0⤋
x^2+3x+4x+12=x^2+7x+12
2007-03-21 20:11:52 · answer #10 · answered by Chris 521n36 1 · 1⤊ 0⤋