I have a closed system which is at X degree celcius. I decide to increase the temperature by 30 degree celsius and make it remain there. The reaction taking place is:
A + B --> C + D (it's a reversible reaction)
(enthalpy change is negative-> Exothermic)
I know the reaction will move to the left, but will the temperature of the system be X? Or X + 10?
I mean the reaction is moving backwards in order to eliminate these disturbance in temperature, will it succeed in lowering the temperature to X? Or will it keep trying?
2007-03-21 19:42:12 · 2 answers · asked by Chocolate Strawberries. 4 in Science & Mathematics ➔ Chemistry
What i mean is that there will be a energy supplier giving constant extra heat.
2007-03-21 19:54:16 · update #1
As it is an exothermic reaction by increasing the temperature of the system the reaction will tend to move backward ie C and D will react to give back A and B . At equilibrium condition the overall temperature of the system will tend to remain static. around X degree Celsius.
2007-03-28 00:47:47 · answer #1 · answered by sb 7 · 0⤊ 0⤋
It will go back to x degrees celsius.
In a closed system, temperature is static, if you add heat energy to the system it will be canceled out until it runs out of product.
2007-03-22 02:49:00 · answer #2 · answered by Siddy 1 · 0⤊ 0⤋