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(x^2-2x+2)=0
The answer's (1+i)(1-i), but I'm not sure how I'd do it in my head. Any tips on simplifying polynomials with imaginary roots?

2007-03-21 17:54:24 · 2 answers · asked by lirael1019 1 in Science & Mathematics Mathematics

2 answers

x^2 - 2x + 2 = 0

The direct way would be to use the quadratic formula. Another way would be to complete the square, like so:

x^2 - 2x + 1 + 1 = 0

x^2 - 2x + 1 = -1

(x - 1)^2 = -1

Take the square root of both sides (remembering to add a "plus or minus"):

x - 1 = +/- sqrt(-1)

But sqrt(-1) = i, so

x - 1 = +/- i

Moving the -1 to the right hand side,

x = 1 +/- i

therefore,

x = (1 + i, 1 - i)

2007-03-21 17:58:29 · answer #1 · answered by Puggy 7 · 0 0

You could use the discriminant first to determine that the roots are imaginary and then the quadratic formula would be the easiest way to go.

2007-03-21 18:23:52 · answer #2 · answered by lizzie 3 · 0 0

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