what is the answer to this polynomial? (2y7 - 7y5 - 3y2 - 3) - (2y7 - 7y5 - 3y - 2)
2007-03-21 17:20:38 · 5 answers · asked by sexyactor,Eric 2 in Science & Mathematics ➔ Mathematics
The answer is -1. All the terms cancell out except for the constant which is -3 --2 or -3 +2 or -1.
2007-03-21 17:24:01 · answer #1 · answered by badaerozepstones 3 · 0⤊ 0⤋
remove the parenthesis first by disttributing the minus sign to the subtrahend:
2y7 - 7y5 - 3y2 -3 -2y7 + 7y5 + 3y +2
Then combine similar terms:
(2y7 - 2y7) + (-7y5 + 7y5) + (-3y2) + (3y) + (-3 +2)
The first two terms equal to zero, so the answer is:
-3y2 +3y -1
2007-03-21 17:30:40 · answer #2 · answered by activista 2 · 0⤊ 0⤋
You use the addition method for this. here's how you do it.
(2y^7 - 7y^5 - 3y^2 - 0y - 3)
-( 2y^7 - 7y^5 - 0y^2 - 3y - 2)
the 2y^7 & 7y^5 cancel out, so now you deal with what is left.
(- 3y^2 - 0y - 3)
- (- 0y^2 - 3y - 2)
so the answer is -3y^2+3y-1)
2007-03-21 17:34:40 · answer #3 · answered by superiorsarin 2 · 0⤊ 0⤋
-3y^2 + 3y - 1
2007-03-21 17:25:57 · answer #4 · answered by Anonymous · 0⤊ 0⤋
-3y² + 3y - 1 is answer.
Note that 2y^(7) - 2y^(7)= 0 = -7y^(5) + 7y^(5)
2007-03-22 00:38:06 · answer #5 · answered by Como 7 · 0⤊ 0⤋