2007-03-21 16:43:02 · 7 answers · asked by help 1 in Science & Mathematics ➔ Mathematics
set the equation in terms of y, so y=(4x^2-7)^0.5. Find dy/dx (the derivative of y with respect to x....i'm assuming you know basic calculus). so dy/dx=(4x)/[(4x^2-7)^0.5]. Plug in x=2 into the equation and you get dy/dx=2.67. hope you find it helpful!
2007-03-21 16:54:04 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Find slope of 4x² - y² = 7 at the point at (2,-3).
Differentiate implicitly.
8x - 2y(dy/dx) = 0
2y(dy/dx) = 8x
dy/dx = 8x/(2y) = 4x/y
Now plug in the point on the curve.
dy/dx = 4x/y = 4*2/-3 = -8/3
The slope of the curve at (2,-3) is -8/3.
2007-03-25 11:47:16 · answer #2 · answered by Northstar 7 · 0⤊ 0⤋
to find the slope, rewrite it in respect to y.
then find the derivative.
m=4x(4x^2 + 7)^-1/2
plug in 2 for x
it should come out to about 1.668
***
sorry i made a mistake, it should be m=4x(4x^2 - 7)^-1/2.
Mr. X is right.
2007-03-21 16:52:33 · answer #3 · answered by vanka 2 · 0⤊ 0⤋
To find the slope/gradient, differentiate both sides to obtain
8x-(dy/dx)(2y)=0
Inserting x=2, y=-3 into the above we have
16-(dy/dx)(-6)=0
Rearranging gives (dy/dx)= - 8/3
Therefore, the gradient of the curve at (2,-3) is (dy/dx) = -8/3
2007-03-21 17:02:28 · answer #4 · answered by Chris 521n36 1 · 0⤊ 0⤋
At the point (2,3) the slope of the curve is 8/3
2007-03-21 16:54:31 · answer #5 · answered by badaerozepstones 3 · 0⤊ 0⤋
4x^2-y^2=7
-y^2=7-4x^2
-y=7-4x
slope= -4
I think that is correct.
2007-03-21 16:52:50 · answer #6 · answered by nessa0505 2 · 0⤊ 0⤋
the answer is 66790653407961406435106 and 2/3
2007-03-21 16:47:26 · answer #7 · answered by Anonymous · 0⤊ 1⤋