Calculate the density in g/cm3 of:?

Question

ethane C2H6 at 118.0oC and 803 torr

Answer 1

PV=nRT I'm not sure what value of R to use, find a chart and use hte apporiate one

We'll make n = 1 mol
P=803 torr, T= 118 + 273 = 391 K

Anywyas, find a Gas constant that has cm^3 in it and uses Kevlin....then you might have to convert your pressure

Solve for V
V=nRT/P

Then find how many grams in 1 mole of C2H6
C2= 24 g/ mol... h6 = 6 g/mol....30 g/mol
30g / mol * 1 mol = 30 g

Then take 30 / V

Just to say, we can make the moles be whatever we want,
they'll cancle eachother out.
But if you chose n = 2 for the first equation.....you'd have to solve the number of grams in 2 moles of ethane.

Answer 2

Density in g/L from the Ideal Gas Law:

d = P*MM/RT = 1.057 atm * 30 g/mol/(0.08206* 391K)
d = 0.988 g/L = 0.000988 g/cm^3