√(2x+8) + 6 = 10.
2007-03-21 16:24:10 · 6 answers · asked by JJ 1 in Science & Mathematics ➔ Mathematics
Ya its 2x +8 under the square root
2007-03-21 16:28:33 · update #1
continue with Dan's solution ....
substitute 4 in the place of x
√(2x+8)+6
=√(2*4+8) + 6
=√16 + 6
= 4 + 6 [Note: √16 = 4 ]
= 10
= RHS
2007-03-21 16:42:54 · answer #1 · answered by Dhananjeyan 3 · 0⤊ 0⤋
√(2x+8) + 6 = 10
√(2x+8) = 10 - 6
√(2x+8) = 4
2x+8 = 4^2
2x+8 = 16
2x= 16-8
2x=8
x=4
hope it is easily understood... : )
2007-03-21 16:44:25 · answer #2 · answered by Slitwrist 1 · 0⤊ 0⤋
x=4. the sq root of 2 times 4(x) plus 8 is 4, 4 plus 6 equals 10.
2007-03-21 16:37:55 · answer #3 · answered by scott k 1 · 0⤊ 0⤋
√(2x+8) + 6 = 10
√(2x+8)=10-6
√(2x+8)=4
2x+8= 4^2
2x+8= 16
2x= 16-8
2x= 8
x= 8/2
x= 4
2007-03-21 16:45:27 · answer #4 · answered by maltese_1992 3 · 0⤊ 0⤋
Subtract six from both sides
(2x+8)^1/2 = 4
Square both sides
2x+8=16
2x=8
x=4
2007-03-21 16:30:35 · answer #5 · answered by Dan 2 · 0⤊ 0⤋
is the entire quantity under the squareroot?
2007-03-21 16:27:26 · answer #6 · answered by Anonymous · 0⤊ 0⤋