This is the instructions....Solve for A. B=7/8(A-9)
2007-03-21 15:55:52 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
B=7/8(A-9)
8(A-9)B=7
8A-72=7/B
A=[(7/B)+72]/8
2007-03-21 16:01:14 · answer #1 · answered by peateargryfin 5 · 0⤊ 0⤋
Isolate the variable A. Solve for A in terms of B.
If the (A-9) is in the denominator:
B(A-9) =7/(8) Multiply both sides by (A-9)
(A-9) = 7/(8B) Divide both sides by B
A-9+9 = [7/(8B)] + 9 Add 9 to both sides
A=[7/(8B)] + 9
However, if it is 7/8 times the quanitity (A-9) it should be posted as:
B = (7/8) (A-9) or as
B = [7(A-9)] / 8 so
8B = 7 (A-9) Multiply both sides by 8
(8B)/7 = (A - 9) Divide both sides by 7
[(8B) / 7] + 9 = A Add 9 to both sides
Hope this helps!
2007-03-21 23:08:34 · answer #2 · answered by mathterp64 1 · 0⤊ 0⤋
B=7/8(A-9)
A-9 = 8B/7
A = 8B/7 n +9
2007-03-21 23:00:21 · answer #3 · answered by laportama 2 · 0⤊ 0⤋
B=7/8(A-9), which also means 7/8 x (A-9)
So,
B= 7/8A - 63/8
B/A= 7/8 - 63/8
B/A= - 56/8
B/A= -7
B= -7A
-B/7=A
So answer is
A= - B/7
2007-03-21 23:11:41 · answer #4 · answered by maltese_1992 3 · 0⤊ 0⤋
8B = 7A - 63
7A = 8B + 63
A = (8/7).B + 9
2007-03-22 07:29:16 · answer #5 · answered by Como 7 · 0⤊ 0⤋