math equation?

Question

write an equation of a line parallel to the given line and passes through the given point.
Y= 2x - 8; (0,-3)

Answer 1

equation of a line passe through a point (x1,y1) is:
Y=m(x-x1)+y1 and parallel to an other have the same slope.
m=slope , (x1,y1)→(0,-3)
Then,
Y=2(x-0)-3 or
Y=2x-3

y=2x-8 and y=2x-3 are parralel.

Answer 2

To get a line parallel to the given line you want a line that has the same slope and possibly a different y intercept.
This line has the form y = mx + b where m is the slope, and b the y intercept.

The slope of y = 2x - 8 is 2, so the new line will have m=2
The y intercept of the new line is given to you since (0, -3) is a point in the new line and this point is on the y axis. Thus b = -3

So the equation you want is

y = 2x - 3

Answer 3

Remember that in the equation of a line, the number before you x is your slope. There for, any line with the same slope and a different y intercept is parallel. Now, the point you have is quite nice since it is your y intercept. That is because the x is zero.
So, you have a slope of 2 and a y intercept of -3, thus

y=2x-3 is a parallel line through (0,-3)

Answer 4

You are fortunate that the point given to you is the point (0, -3) Since x is 0, the point is on the y-axis. Thus the y intercept is -3. Since the line is parallel, the slope is the same, and your equation is y=2x-3.

Answer 5

y=mx+c is the equation of a straight line

m is the gradient

a line parallel will have the same gradient.

y=2x+c

when x=0; y=-3

ie. the y intercept is -3 which is what c represents

y=2x-3

Answer 6

If it's parallel, it has the same slope, so it's

Y=2x+b because Y=mx+b

now plug in

-3=2*0+b
-3=b

so the equation is...

Y=2x-3
or atleast, it should be.

<3
stranger.

(best wishes)

Answer 7

y=2x-3. Easy.

Answer 8

y = 2x -3

Answer 9

y=2x-3

Answer 10

y-y1=m(x-x1)

y+3=2(x-0)

y=2x-3