Say you are given the probabilities to 3 independent events (A, B, and C) and you want to find the probability that at least one is true. It would be P(A) + P(B) + P(C) + (A and B) etc. When calculating these would it just be the probability of A or would it be the probability of A times 1-probability of B times 1-probability of C? In other words, is the probability of A and B just as simple as the probability of A times B or do we need to find the probability of A times B times the failure of C?
2007-03-21 15:43:38 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Well, if i understand this right, you have Pa, Pb, Pc 3 independent probabilities.
And you want the probability that at least one happens, then it's like this
(1-Pa)(1-Pb)(1-Pc) = probability that none will happen
Probability that atleast one will is: 1 - (above equation)
hope it helps.
2007-03-21 15:49:02 · answer #1 · answered by gabriell_021 2 · 1⤊ 0⤋
If you want the probability that at least one event is true, the easiest way to do it is to figure out the probability that NONE of the events is true.
Subtract that probability from 1, and you get the probability that at least one is true.
In other words, your probability is 1 - P(not A) * P(not B) * P(not C).
2007-03-21 15:49:06 · answer #2 · answered by Bramblyspam 7 · 0⤊ 0⤋
P(at least one is true)=1-P(all are false)
= 1- P(A false)*P(B false)*P(C false).
2007-03-21 15:49:28 · answer #3 · answered by fcas80 7 · 0⤊ 0⤋
no
2007-03-21 15:48:13 · answer #4 · answered by Anonymous · 0⤊ 0⤋