I really need help on this?

Question

Find the points at which y = f(x) = x^10−6x has a global maximum and minimum on the interval 0 ≤ x ≤ 3.5.

Answer 1

f'(x) = 0 gives you the critical value. It is (0.6)^(1/9). Let's call that number c.

To find absolute (or global) max and mins on an interval, plug in the endpoints of the interval (in this case 0 and 3.5) as well as any critical values, in this case our c. Whichever yields the largest f(x) is the global max and the smallest f(x) is the global min.

Answer 2

find derivative

y' = 10x^9 - 6

let y' = 0 so 10x^9 - 6 = 0

solve for x (there is only one x call it x1)

find f(x1), f(0) and f(3.5)

any of these value which is greatest is max and the lowest is the min

Answer 3

A what what!!!??? I have no idea what ur saying.