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calculate the volume of products formed when 5 grams of C3H8O reacts in excess O2. Then calculate the pressure exerted by the gaseous products if the reaction occurs in a 3.78L container at 25 dergree in celsius.

2007-03-21 15:27:46 · 2 answers · asked by Anonymous in Science & Mathematics Chemistry

2 answers

This is the method. You can calculate the details.

The full reaction should have CO2 and H2O as products. You need to balance the equation.

Convert the 5 grams to moles by dividing by the molecular mass of the C3 compound. Then use the molar ratios to calulate the moles of CO2 and H2O (vapor, not liquid).

Convert the moles of gas to volume by multiplying 22.4 L /mol.

Now adjust the volume of gas from STP to your conditions using the gas law P1V1/T1 =P2V2/T2

Solve for P2 and you are done.

2007-03-21 15:47:09 · answer #1 · answered by reb1240 7 · 0 0

THe question doesn't say what the reaction IS! So I'll assume its combustion.
1. Write the equation
2. use the equation to figure the number of moles produced of H2O and CO2
3. figure what the idiot meant by "the gaseous products". I hope the poor excuse for a teacher who wrote this problem isn't tenure track. He/She could be talking about all the products being gasseous (but at 25C water is a liquid) or just the CO2
or the CO2 and the amount of water which would saturate a volume of 3.78 L at 25C ( 100% relative humidity). The actual concentration of water vapor at 25C would have to be looked up but it might be less than what the 5 g would produce or might not.
C3H8O + O2 -> CO2 + H2O
not balanced!
C3H8O + 5O2 => 3CO2 + 4H2O
H and C balance but not O!!!
C3H8O + 4.5O2 => 3CO2 + 4H2O
finally!
1 mole of MethylEthyl Ether reacts to form 3 moles of CO2 and 4 moles of water. So how much does 5 g or methylethylether make? Figure out how many moles it is and do the proportion!
then use PV=nRT to figure P
THe "best" answer is to do the work to figure that the 3.78L is at 100% RH (if there's enuff H2O) and that the rest of the water is liquid. The second best answer is to assume the water will eventually condense out and not contribute to the pressure. First case n is both water and CO2, second case n is for just CO2. Good luck

2007-03-21 22:57:23 · answer #2 · answered by Anonymous · 0 0

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