meters per seconds squared
2007-03-21 15:16:52
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answer #1
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answered by UFgirl 2
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It stands for meters per second squared (or meters per second per second), a unit of acceleration. Basically, it's a measure of change in velocity/speed (which can be measured in meters per second [or miles per hour or anything that's a distance over a time]). So what, say, 1 m/s^2 means is that the speed of an object will change by one meter per second every second. So, starting with no speed, after one second an object would have a speed of 1 m/s, after two seconds 2 m/s, ater three seconds 3 m/s, and so on.
2007-03-21 22:46:30
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answer #2
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answered by DAG 3
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It is a Gravity unit, but more specifically it is the Acceleration due to Gravity.
It stands for meters per second squared. On Earth it is approximately 9.81 meters/ second ^ 2. Or as my Physics teacher says 9.81 meters per second per second. Every second your velocity increases by 9.81 meters per second.
The mathematical notation for this value is "g"
2007-03-22 02:03:45
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answer #3
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answered by Anonymous
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This is the unit of accleration. In Newton's Law,
F = m a, where a= accleration. On earth, the accleration due to gravity is 9.8 m/sec^2, which roughly means that whatever the velocity of a free-falling object was at t seconds, it will be 9.8 m/sec more at t+1 seconds.
2007-03-21 22:19:12
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answer #4
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answered by cattbarf 7
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This is a unit of acceleration. Another way of looking at it is I am increasing my velocity by, say, 12 meters per second every second i.e meters per second squared.
2007-03-21 22:20:35
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answer #5
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answered by Kyle M 1
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that means meters per second per second (kind of confusing) but meters per second is already a unit of accelleration, so this just simply means that for every second that you fall (or travel horizontally), you speed up X meters/second (on earth, it's 9.81 m/s^2).
2007-03-22 00:05:08
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answer #6
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answered by mcdonaldcj 6
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"Meters divided by seconds squared" which is the standard metric unit for acceleration.
2007-03-21 22:18:13
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answer #7
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answered by evokid 3
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acceleration
2007-03-21 22:17:26
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answer #8
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answered by ip 2
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